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求xydx-(1+y2)√(1+x2)dy=0且y当x=0时等于1/e 求解?_知乎
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\[\begin{gathered} xydx - (1 + {y^2})\sqrt {1 + {x^2}} dy = 0,xydx = (1 + {y^2})\sqrt {1 + {x^2}} dy, \hfill \\ \frac{x}{{\sqrt {1 + {x^2}} }}dx = \frac{{1 + {y^2}}}{y}dy,\int {\frac{x...更多
知乎 - www.zhihu.com/q...- 2023-3-2